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-5x^2-15x+155=0
a = -5; b = -15; c = +155;
Δ = b2-4ac
Δ = -152-4·(-5)·155
Δ = 3325
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3325}=\sqrt{25*133}=\sqrt{25}*\sqrt{133}=5\sqrt{133}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-5\sqrt{133}}{2*-5}=\frac{15-5\sqrt{133}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+5\sqrt{133}}{2*-5}=\frac{15+5\sqrt{133}}{-10} $
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